Route Transposition and Phenomenon

[Jarlve]

I have a gmail account. I clicked on "Drive" which has a symbol that looks like a recycle triangle. Then I made a folder, pasted the files into the folder and pasted the link onto this site.

What about row 18? It looks pretty warm in the tests as well. And when I do just the top half, rows 4, 6 and 10 are warm.

Ahhh... maps can be linked too. Thank you.

Made a horizontal specific slide test and here are the results, these should be a more accurate than what the grid and periodic tests can do for horizontal fragments: https://drive.google.com/open?id=0B5r0r ... HhaNDFBdzQ

[Jarlve]

Made 10 ciphers with different plaintext and about 20% random homophone selection (cycle randomization). 2 ciphers had similar rows as the 340. In the first cipher removal of one of the affected rows does only increase perfect n-symbol cycles marginally and in the second cipher removal of the affected row caused a very long perfect 2-symbol cycle to appear.

I could try to stack different cycle measurements to validate eachother.

Code: Select all

1  2  3  4  5  6  7  8  6  9  10 11 12 13 14 14 5
15 16 17 18 19 18 20 17 21 19 22 23 24 25 10 26 27
28 6  1  29 25 30 31 32 27 8  5  2  33 34 1  35 10
36 5  11 37 15 33 38 2  31 32 39 9  10 11 9  30 29
24 17 40 41 20 42 3  4  5  23 43 10 2  44 5  18 17
15 45 1  8  10 19 32 46 25 34 47 5  9  11 48 17 14
49 39 19 50 7  51 18 5  26 18 29 10 32 52 45 53 54
24 11 4  38 17 40 41 23 55 5  30 32 31 2  46 47 29
10 34 27 28 6  33 1  32 14 29 49 47 21 19 32 56 11
23 48 22 27 10 51 57 33 13 28 26 39 8  5  17 9  19
6  58 10 30 45 38 1  53 50 28 36 29 5  23 47 40 59
6  27 43 10 49 60 32 28 8  18 13 44 5  51 41 29 10
2  33 51 55 56 42 24 9  18 36 1  29 2  58 15 25 38
46 53 27 34 33 27 19 55 7  32 8  5  26 33 28 42 28
30 24 11 18 28 17 3  40 56 25 17 1  5  49 54 19 31
32 16 61 21 51 52 11 53 50 41 50 59 40 18 9  10 17
28 36 8  5  23 47 49 7  19 6  48 62 16 51 29 10 32
21 5  53 40 4  15 48 14 57 11 39 8  28 13 20 24 2
58 17 18 28 19 22 49 44 25 32 1  9  51 24 3  10 34
27 41 59 26 11 45 4  33 28 7  30 31 23 8  25 36 9

AZdecrypt encoding randomization stats for: m3.txt
----------------------------------------------------
- Attempts to detect encoding randomization from the
input given that it has sequential properties.
- A higher percentage (improvement rate) may be
more indicative of randomization.

Rows, randomize characters, using 2-symbol cycles:
----------------------------------------------------
Row 1: 24.85%
Row 2: 3.55%
Row 3: 65.23% <---
Row 4: 51.21% <---
Row 5: 0.06%
Row 6: 0.66%
Row 7: 0.04%
Row 8: 0.69%
Row 9: 2.55%
Row 10: 0.16%
Row 11: 0.13%
Row 12: 2.02%
Row 13: 3.63%
Row 14: 0.41%
Row 15: 0.1%
Row 16: 0.44%
Row 17: 0.64%
Row 18: 0.01%
Row 19: 0%
Row 20: 0%
--------------------
Average: 7.81%


Code: Select all

1  2  3  4  5  6  7  8  9  10 11 12 13 1  14 15 16
17 14 18 19 20 21 5  22 23 24 25 26 7  14 1  27 28
29 30 20 31 32 33 34 35 2  36 37 7  26 29 11 38 14
1  8  4  39 40 22 25 41 42 13 35 20 43 44 9  10 7
15 45 41 5  46 47 27 48 1  2  41 49 4  1  19 11 30
1  5  28 25 50 51 33 52 43 53 47 40 31 15 23 28 2
13 54 21 14 1  24 20 28 29 7  34 14 36 32 27 38 30
55 20 4  48 7  56 24 8  51 16 51 11 21 26 25 50 37
14 35 29 15 16 33 2  54 40 22 42 13 57 27 58 18 4
16 10 30 36 6  35 27 48 5  36 1  25 33 21 48 2  32
17 40 50 49 26 56 54 29 20 52 4  55 7  13 38 57 14
30 8  39 20 24 9  47 7  28 25 23 14 18 2  29 15 36
59 2  12 51 20 24 28 4  60 7  29 35 27 48 31 9  29
33 23 12 10 14 28 24 40 20 34 16 25 41 51 13 37 25
42 41 40 26 7  6  4  1  49 11 55 14 13 21 15 50 1
30 16 33 22 42 25 29 20 55 7  24 34 27 35 29 14 1
27 54 1  22 20 26 5  24 7  21 10 14 1  5  46 19 23
56 29 40 31 17 61 57 2  62 34 11 58 58 32 39 30 37
16 4  28 29 40 20 34 21 15 18 1  28 27 24 13 22 47
63 51 56 32 31 2  14 55 20 29 30 34 15 57 4  30 18

AZdecrypt encoding randomization stats for: m10.txt
----------------------------------------------------
- Attempts to detect encoding randomization from the
input given that it has sequential properties.
- A higher percentage (improvement rate) may be
more indicative of randomization.

Rows, randomize characters, using 2-symbol cycles:
----------------------------------------------------
Row 1: 0.52%
Row 2: 0.22%
Row 3: 0.01%
Row 4: 0.01%
Row 5: 0.98%
Row 6: 0.05%
Row 7: 0.02%
Row 8: 0.02%
Row 9: 1.05%
Row 10: 3.08%
Row 11: 0.01%
Row 12: 0.14%
Row 13: 6.34%
Row 14: 11.17%
Row 15: 0.3%
Row 16: 26.22%
Row 17: 1.48%
Row 18: 0.26%
Row 19: 7.52%
Row 20: 72.45% <---
--------------------
Average: 6.59%


[smokie treats]

You made messages with random symbol selection to find out if the heatmap would find rows comparable to the 340, then deleted the rows to find out if the cycle scores would increase as much as the 340 when you delete row 14?

[Mr lowe]

Jarlve
I am not up to speed with the heat map set up yet. I do have a question though. Using the 408 if you swap row 24 (the last row) and row 14 how does that react.
come to think of it I probably have the same question for the 340 swap row 14 to the last row rather than delete. just to see how it looks.

[Jarlve]

You made messages with random symbol selection to find out if the heatmap would find rows comparable to the 340, then deleted the rows to find out if the cycle scores would increase as much as the 340 when you delete row 14?

20% random homophone selection can cause the test to show up rows like in the 340. Though I want to dig a little bit further. It seems that whole rows can be affected by a much smaller fragment inside (the whole in the part). Symbol cycles can inflate and deflate very rapidly with randomization. Will try a few things.

@Mr lowe, swapping these rows introduces 3 new symbols to the 340 and 4 to the 408. Row 14 in the 340 is so bad that almost anything will improve it and so it did. In the 408, glurk showed that the last line contained many fragments that were dropped down vertically. Looking a bit further here we can see below that the last row creates 2 omnidirectional trigrams and 1 omnidirectional quadgram. Not sure what to think about that.

Code: Select all

                 
                 
    UIk         
                 
                 
         6       
         q       
        qEHM     
        q       
       6         
     WI         
            
                 
 I               
 U               
 =               
                 
                 
                 
                 
                 
                 
                 
VEXr9WI6qEHM)=UIk


[Mr lowe]

Jarlve. sorry but i think my translation was lost, What i wanted to see with the 408 heat map was the last row filler being moved and highlighted at row 14. It should not produce any new symbols. (its the same code reorganised)
swap the last row of the 408 with row 14 of the 408 to see if the heat map showed something similar at row 14. more of a test than anything.
PS for the 408 you can swap the last row with any row but 14 seems like as good a row as any.

Again do the same with the 340. a straight swap. row14>20 row20>14 What i`m looking for is a way that the 340 ends up with a "possible" filler at row 14.
cheers.

[Jarlve]

New idea, cycle assisted solving. Going under the assumption that the 340 is a homophonic substitution cipher. Then a plaintext of any merit should have a more cyclic plaintext to ciphertext key. Following are a few examples, smokie18e has a low scoring hard to make out plaintext and is less cyclic than than the 340, yet it scores better.

408 plaintext to ciphertext key with cycles scores:

Code: Select all

Input to output key:
----------------------------------------------------
I: 9PUk9PUk9PUk9PUk9PUk9PUk9PUk9PUk9P99U99PP9Uk (3968)
L: %B%B#B%B#B#B#B%#B%%%%#B#B%%#B##%B (330)
K: ////// (0)
E: ZpW+6NEZpW+6NEEZpW+6NEZpW+6NENZpW+6NEZpW++WZE6Z+W6EW6E (3542)
N: O^D(O^D(O^D(O^D(O^DO^DO (960)
G: RRRRRRRRRRRR (0)
P: ======= (0)
O: X!TdXTdX!TdX!TXTdT!XXd!dXTX (360)
B: VVVVVVVVV (0)
C: eeeeeeeeee (0)
A: G7Sl8G8Sl8GS8l8G8lSl7GS8SG7G8 (30)
U: YYYYYYYYYY (0)
S: F@KF@K@KF@KF@KFF@ (330)
T: HI5LHI5ILHI5LHI5LHI5LHI5LI5LHL5IIHI (1680)
M: qqqqqqqqqqqqqqqq (0)
H: M)M)M)M)M)M)M)M) (420)
F: JQJQJQJQJJQ (144)
R: tr\tr\tr\tr\trt\trr (546)
W: AAAAAAAA (0)
D: fzzfzfz (40)
V: cccccc (0)
X: j (0)
Y: ________ (0)
--------------------
Cycle score: 12350


smokie18e plaintext to ciphertext with cycle scores:

Code: Select all

Input to output key:
----------------------------------------------------
A: >>`19B>1`B>`9B```1`9`B>9`19>>`B>`9B>`B> (60)
S: ^D:$88::$$8:$^DD^8:8$:D::8:^DD (10)
T: WWWF,WW,WWF,,*WF*,WFWW,W,W,WW*WW (48)
E: ZI[ZI[ZZIZZZI[ZI[ZI[ZZIZ[ZZ[[ZI[ZZIZ[IIZZI (1026)
R: 6<0<6A0<<<<<06J<A06<J6A<<< (60)
C: +e+++Ce+ (6)
D: OcOKKOOcKOOcOKK (36)
I: g4a]g4ga]4]4]agg]g44a] (120)
N: Y)2fY))Yf)2f)7f2))f)Y))7) (0)
L: MMM5M#55MP5M#PM (8)
O: Q.S.....Q.S..QQS....S........ (18)
W: GGG(GG( (12)
H: --R/R-R-R--R-//R (18)
B: ;;&;&; (24)
U: NT"NNNNT" (18)
F: U_UU (4)
M: b\bL\LL (6)
P: VVVV (0)
Y: hhh (0)
G: % (0)
--------------------
Cycle score: 1474


340 plaintext to ciphertext with cycle scores:

Code: Select all

Input to output key:
----------------------------------------------------
G: HH33HH (4)
S: Epp##ppp_p-##_6-p-Ep6#E-p6p_-p (0)
H: RR&RRRR&RR (24)
I: >O*J*OjO*>JjOJOOJ**>OOO*>O (30)
C: lZllXZlllXZlZ (36)
E: ^1NB<Bz^z4^zNz<B4z^<BB<4BzNBN^44B14zB^1<Bz<BBNz (0)
N: VTMSVMVMVTMTMSVVMTSTMS (48)
T: P2++8++2+P+82+22++++2+++2++82+++2++++P8+ (0)
O: k)U)5kk5U@UU5555U5)))kk (0)
P: |7|C|7|||C|C|C|7C| (60)
R: LWWLtFFFLLFFtFFFtLFWLWWFWt (8)
A: GDKcGKDKcGGbcKDbKccGbccKGcccDK (0)
M: ddddd (0)
L: (%Y((%(YY(((Y (18)
D: .y.yy.y.y.. (112)
V: f:ff:f (24)
U: 9999 (0)
F: /// (0)
B: qq (0)
Y: ;A;A; (24)
--------------------
Cycle score: 388


[Jarlve]

Jarlve. sorry but i think my translation was lost, What i wanted to see with the 408 heat map was the last row filler being moved and highlighted at row 14. It should not produce any new symbols. (its the same code reorganised)
swap the last row of the 408 with row 14 of the 408 to see if the heat map showed something similar at row 14. more of a test than anything.
PS for the 408 you can swap the last row with any row but 14 seems like as good a row as any.

Again do the same with the 340. a straight swap. row14>20 row20>14 What i`m looking for is a way that the 340 ends up with a "possible" filler at row 14.
cheers.

That was a good idea Mr lowe: https://drive.google.com/open?id=0B5r0r ... GhTbkNpdDQ

In the 408 the map now hilights row 14 but in the 340 this does not happen as much. I think this could mean that row 14 in the 340 is not filler such as the last row of the 408.

[Mr lowe]

Jarlve. sorry but i think my translation was lost, What i wanted to see with the 408 heat map was the last row filler being moved and highlighted at row 14. It should not produce any new symbols. (its the same code reorganised)
swap the last row of the 408 with row 14 of the 408 to see if the heat map showed something similar at row 14. more of a test than anything.
PS for the 408 you can swap the last row with any row but 14 seems like as good a row as any.

Again do the same with the 340. a straight swap. row14>20 row20>14 What i`m looking for is a way that the 340 ends up with a "possible" filler at row 14.
cheers.

That was a good idea Mr lowe: https://drive.google.com/open?id=0B5r0r ... GhTbkNpdDQ

In the 408 the map now hilights row 14 but in the 340 this does not happen as much. I think this could mean that row 14 in the 340 is not filler such as the last row of the 408.

Yes Jarlve that seems to be the case.

[smokie treats]

I think that the cycle test results, although circumstantial and inconclusive regarding the pivots, do add to what we know about the 340 and work with other test results. I see three possible explanations for the pivots, not necessarily in this order:

1. The pivots are a naturally occurring result of the cipher, except that we can't figure out how to make a cipher with improbable period 29 / 39 bigram repeats in count, improbable period 15 / 19 repeats in count and symbol count, and pivots. And two pivots are highly improbable in any cipher that we can think of.

2. Zodiac was unaware of the period 15 / 19 and 29 / 39 repeats he was creating, which seems likely. None of the cryptography books describing transposition also discuss advanced period detection. But then he got extremely lucky when intentionally writing the pivots to either play some kind of game or give us a hint as to what he did, and he wrote the pivots at the same exact period as the period 29 / 39 spike. There would still be a period 29 spike without the pivots.

3. Zodiac, although the cryptography books didn't discuss advanced transposition period detection, somehow had an advanced knowledge of them and realized that he was creating period 29 / 39 bigram repeats. And he wrote the pivots as a clue to what he did.

Which of the above scenarios seem more likely?

Of course, recent cycle testing shows dark rows where the pivots are. Of course it does.

Jarlve, thanks for posting your work in this thread!