mike_r wrote:Hi-
KQ's mother died on December 20, 1939. His father was born on September 27, 1887. On July 5, 1947, KQ claimed he not only saw flying saucers over Auburn, CA but that he knew that they were space crafts. Nobody else at the time (only two weeks after the term "flying saucer" was created) was venturing such a guess, civilians or scientists. His story appeared on the frunt page of the SF Examiner on July 8th). Attention seeking on a grand scale. On October 11, 1958, KQ ran his first race car at the Riverside International Speedway.
Anyone see a pattern here?
You are wandering into "pure coincidence" territory here. As in, you have to definitively exclude the possibility that significant dates match due to random chance. What are the odds that KQ's personally significant dates would match 4 of Zodiac's personally significant dates? How low do those odds have to be to prove they aren't coincidence?
We can try the
5% rule. If the chances are less than 5%, then maybe the matching of dates was by design.
Let's do a quick thought experiment. How many dates do you think are personally significant to the Zodiac killer? Let's say there are 10 such dates. They would include crime dates and perhaps other notable events known only to the killer.
There are a number of dates that are personally significant to KQ. Birth dates, death dates, notable life events, and so on. How many of those dates are needed for there to be more than a 5% chance that they match at least 4 of the 10 Zodiac dates purely by chance?
(Warning: Math)
The chance that one KQ date matches one Zodiac date is: 10/365.
The chance that 4 KQ dates each match one of the Zodiac dates is: (10/365)*(10/365)*(10/365)*(10/365), or 10/365 raised to the 4th power, which is a pretty small number.
Let's say N is the number of significant KQ dates. There are (N choose 4) ways to pick 4 of them.
So we can write (N choose 4)*((10/365)^4) = p, where p represents the probability we matched 4 of KQ's dates with 4 of Zodiac's dates.
If p is at least 5% then we are not confident the dates match up by design.
Thus we want (N choose 4)*((10/365)^4) >= 0.05
That works out to about 40 dates.
Conclusion: You only need to find 40 dates significant to KQ for there to be a 5% chance that they match 4 of Zodiac's dates purely by accident. You could pick from KQ's kids' birthdays, his parent's birthdays, birth and death dates of his relatives, accomplishments in his life, etc. etc. It does not take long to find enough dates.
For comparison, let's say there are 20 significant Zodiac dates instead of 10. In this case, you'd only need to find about 20 dates significant to KQ before you can't escape the shadow of a doubt.
Now let's look at the other part of your claim, where 2 Zodiac dates fall within 5 days of a major holiday.
(Warning: Math)
A random date has a (11/365) chance of falling within 5 days of Christmas, and a (11/365) chance of falling within 5 days of Independence Day. So the random date has a 2*11/365 = 6% chance of falling within one of two major holidays.
If you pick two random dates, the chance that they BOTH fall within 5 days of 2 holidays is: 6% * 6% = 0.36%.
If we have 4 Zodiac crime dates to pick from, there are 6 different ways to pick two of them. So the chance that 2 of the 4 crime dates fall within 2 holidays is: 6 * 0.36% = 2.16%.
But we haven't considered other major holidays. What if we included Halloween and Thanksgiving?
After doing the math, the chance that two of four Zodiac crime dates both fall within one of four possible holidays is: 6*((44/365)^2) = 8.7%
8.77% is high enough for this to be purely coincidental. It gets worse if you include more crime dates.
So again, we have not escaped the shadow of a doubt.
Also, someone please check my math for mistakes!